Exponentials and Logarithms

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Question 2
Medium44%

Giving your answers to 2 decimal places, solve the simultaneous equations

e2y=x+1ln⁡(x−2)=2y−1 \begin{aligned} e^{2y} &= x + 1 \\ \ln(x - 2) &= 2y - 1 \end{aligned} e2yln(x−2)​=x+1=2y−1​
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Exponentials and Logarithms Questions

  1. AS Level
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