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AS Level Maths CCEA
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Exponentials and Logarithms
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How do you solve
2x+1=642^{x+1}=64
2
x
+
1
=
64
without using logarithms?
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Rewrite 64 as
262^6
2
6
Equate indices:
x+1=6x+1=6
x
+
1
=
6
x=5x=5
x
=
5
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Exponentials and Logarithms Flashcards
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Exponentials and Logarithms
