In an electron diffraction experiment, electrons are accelerated from rest through a potential difference $V$ and are incident on a thin crystalline target.

Show that the de Broglie wavelength $λ\lambda$ of an electron accelerated from rest through a potential difference $V$ is given by:

\lambda = \frac{h}{\sqrt{2m_e eV}}

where $h$ is Planck's constant, $m_e$ is the electron mass, and $e$ is the elementary charge.

In a particular experiment, the crystalline target has an interatomic spacing of $nm0.12\text{ nm}$ . To produce a clear diffraction pattern, the de Broglie wavelength of the electrons must be equal to $40%40\%$ of this spacing.

Calculate the required potential difference $V$ to 2 significant figures.

State and explain how the appearance of the diffraction pattern on the screen changes if the potential difference $V$ is increased.

In an electron diffraction experiment, electrons are accelerated from rest through a potential difference $V$ and are incident on a thin crystalline target.

Show that the de Broglie wavelength $λ\lambda$ of an electron accelerated from rest through a potential difference $V$ is given by:

\lambda = \frac{h}{\sqrt{2m_e eV}}

where $h$ is Planck's constant, $m_e$ is the electron mass, and $e$ is the elementary charge.

Calculate the required potential difference $V$ to 2 significant figures.

State and explain how the appearance of the diffraction pattern on the screen changes if the potential difference $V$ is increased.

Wave-particle duality (A-level only)

Question 1

Markscheme

Wave-particle duality (A-level only)

Question 1

Markscheme

Wave-particle duality (A-level only)

Question 1

Wave-particle duality (A-level only) Questions

Wave-particle duality (A-level only)

Question 1

Wave-particle duality (A-level only) Questions