x2−8x−29≡(x+a)2+bx^2 - 8x - 29 \equiv (x + a)^2 + bx2−8x−29≡(x+a)2+b, where a a\,a and b b\,b are constants.
Find the value of a a\,a and the value of bbb.
Hence, or otherwise, show that the roots of
x2−8x−29=0 x^2 - 8x - 29 = 0 x2−8x−29=0are c±d5c \pm d\sqrt{5}c±d5, where c c\,c and d d\,d are integers to be found.
18 exam-style questions on Edexcel A Level Old Maths Algebra and Functions 1. Each one has a worked solution and a mark scheme showing where the marks go.