The point P P\,P lies on the curve with equation
y=4e2x+1. y = 4e^{2x+1}. y=4e2x+1.The yyy-coordinate of P P\,P is 8.
Find, in terms of ln2\ln 2ln2, the xxx-coordinate of PPP.
Find the equation of the tangent to the curve at the point P P\,P in the form y=ax+by = ax + by=ax+b, where a a\,a and b b\,b are exact constants to be found.
7 exam-style questions on Edexcel A Level Old Maths Logs. Each one has a worked solution and a mark scheme showing where the marks go.