Show that the equation
5cos2x=3(1+sinx) 5 \cos^2 x = 3(1 + \sin x) 5cos2x=3(1+sinx)can be written as
5sin2x+3sinx−2=0. 5 \sin^2 x + 3 \sin x - 2 = 0. 5sin2x+3sinx−2=0.Hence solve, for 0≤x<360∘0 \leq x < 360^\circ0≤x<360∘, the equation
5cos2x=3(1+sinx), 5 \cos^2 x = 3(1 + \sin x), 5cos2x=3(1+sinx),giving your answers to 1 decimal place where appropriate.
10 exam-style questions on Edexcel A Level Old Maths Trigonometry. Each one has a worked solution and a mark scheme showing where the marks go.