Use the binomial expansion to expand
(9−4x)−12∣x∣<94 (9 - 4x)^{-\frac{1}{2}} \quad |x| < \frac{9}{4} (9−4x)−21∣x∣<49in ascending powers of xxx, up to and including the term in x2x^2x2, giving each coefficient as a fully simplified fraction.
Given that the series expansion of f(x)f(x)f(x), in ascending powers of xxx, is
2+49x+px2+…where p is a constant 2 + \frac{4}{9}x + px^2 + \dots \quad \text{where } p \text{ is a constant} 2+94x+px2+…where p is a constantfind the value of kkk,
find the value of ppp.