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4.8 Kinematics (A-level only)

4.8 Kinematics (A-level only)

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Question 6

A particle P P\,P moves with constant acceleration (2i−3j)(2\mathbf{i} - 3\mathbf{j})(2i−3j) m s−2^{-2}−2. At time t=0t = 0t=0, P P\,P is at the origin O O\,O and is moving with velocity (2i−2j)(2\mathbf{i} - 2\mathbf{j})(2i−2j) m s−1^{-1}−1.

a.

Find the speed of P P\,P at time t=2t = 2t=2 s.

[3]
b.

Show that the position vector of P P\,P at time t=2t = 2t=2 s is (8i−10j)(8\mathbf{i} - 10\mathbf{j})(8i−10j) m.

[2]
Markscheme

4.8 Kinematics (A-level only) Questions

  1. A Level
  2. /Maths
  3. /4.8 Kinematics (A-level only)

163 exam-style questions on WJEC A Level Maths 4.8 Kinematics (A-level only), covering 4.8.1 Kinematics (A-level only), 4.8.2 Kinematics (A-level only), and 4.8.3 Kinematics (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.

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