A particle P P\,P moves with constant acceleration (2i−3j)(2\mathbf{i} - 3\mathbf{j})(2i−3j) m s−2^{-2}−2. When t=0t = 0t=0 the particle is at the point A A\,A and is moving with velocity (−3i+5j)(-3\mathbf{i} + 5\mathbf{j})(−3i+5j) m s−1^{-1}−1.
At time t=Tt = Tt=T seconds the particle is moving in the direction of the vector (3i−4j)(3\mathbf{i} - 4\mathbf{j})(3i−4j).
Find the value of TTT.
At time t=4t = 4t=4 seconds, P P\,P is at the point BBB. Find the distance ABABAB.
163 exam-style questions on WJEC A Level Maths 4.8 Kinematics (A-level only), covering 4.8.1 Kinematics (A-level only), 4.8.2 Kinematics (A-level only), and 4.8.3 Kinematics (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.