It is given that k k\,k is a constant.
Find ∫(kx3+2x)dx\displaystyle\int\left(\dfrac{k}{x^3} + 2x\right)dx∫(x3k+2x)dx, giving your answer in its simplest form.
Find the value of k k\,k such that ∫12(kx3+2x)dx=12\displaystyle\int_1^2\left(\dfrac{k}{x^3} + 2x\right)dx = 12∫12(x3k+2x)dx=12
160 exam-style questions on WJEC A Level Maths 1.8 Integration, covering 1.8.1 Integration, 1.8.2 Integration, and 1.8.3 Integration. Each one has a worked solution and a mark scheme showing where the marks go.