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3.7 Integration (A-level only)

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Question 37

Use the substitution u=x3−1u = x^3 - 1u=x3−1 to find ∫134x2(x3−1)2dx\int_1^3 4x^2(x^3 - 1)^2 dx∫13​4x2(x3−1)2dx.

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3.7 Integration (A-level only) Questions

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