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3.6 Differentiation (A-level only)

3.6 Differentiation (A-level only)

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Question 150

The temperature, TTT degrees Celsius, of a cooling laser component ttt minutes after activation is modeled by the function T=f(t)T = f(t)T=f(t) for t>0t > 0t>0.

It is given that:

  • the point P(4,10)P(4, 10)P(4,10) lies on the curve T=f(t)T = f(t)T=f(t)
  • the rate of change of temperature is f′(t)=12t+kt2f'(t) = 12\sqrt{t} + \frac{k}{t^2}f′(t)=12t​+t2k​, where kkk is a constant
  • the rate of change of temperature, f′(t)f'(t)f′(t), has a stationary point at PPP
a.

Find the exact value of kkk.

[3]
b.

Determine an expression for f(t)f(t)f(t), giving your answer in its simplest form.

[5]
Markscheme

3.6 Differentiation (A-level only) Questions

  1. A Level
  2. /Maths
  3. /3.6 Differentiation (A-level only)

333 exam-style questions on WJEC A Level Maths 3.6 Differentiation (A-level only), covering 3.6.1 Differentiation (A-level only), 3.6.2 Differentiation (A-level only), 3.6.3 Differentiation (A-level only), 3.6.4 Differentiation (A-level only), 3.6.5 Differentiation (A-level only), 3.6.6 Differentiation (A-level only), 3.6.7 Differentiation (A-level only), and 3.6 Differentiation (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.

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