A high-precision cam profile in a mechanical sensor follows a path defined by the equation
x=6sin4θ0≤x≤6,0≤θ≤π8 x = 6 \sin 4\theta \quad 0 \le x \le 6, \quad 0 \le \theta \le \frac{\pi}{8} x=6sin4θ0≤x≤6,0≤θ≤8πwhere xxx is the horizontal displacement in millimetres and θ\thetaθ is the angular position of the cam in radians.
Find dxdθ\frac{dx}{d\theta}dθdx in terms of θ\thetaθ.
Hence show that
dθdx=k36−x2 \frac{d\theta}{dx} = \frac{k}{\sqrt{36-x^2}} dxdθ=36−x2kwhere kkk is a constant to be determined.
A specific calibration point P(a,b)P(a, b)P(a,b) lies on the profile. At this point:
Determine the exact values of aaa and bbb.
333 exam-style questions on WJEC A Level Maths 3.6 Differentiation (A-level only), covering 3.6.1 Differentiation (A-level only), 3.6.2 Differentiation (A-level only), 3.6.3 Differentiation (A-level only), 3.6.4 Differentiation (A-level only), 3.6.5 Differentiation (A-level only), 3.6.6 Differentiation (A-level only), 3.6.7 Differentiation (A-level only), and 3.6 Differentiation (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.