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3.6.6 Differentiation (A-level only)

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Question 4

The cross-section of a designer architectural arch is modelled by the curve shown in a coordinate plane, with the equation

x=16sin⁡2y+3,0⩽y⩽π2 x = 16\sin^2 y + 3, \quad 0 \leqslant y \leqslant \frac{\pi}{2} x=16sin2y+3,0⩽y⩽2π​

where x x\,x and y y\,y are spatial coordinates measured in decimetres. The point P(k,π6)P\left(k, \frac{\pi}{6}\right)P(k,6π​) lies on the curve.

a.

Verify that k=7k = 7k=7.

[1]
b.

(i) Find dxdy\frac{dx}{dy}dydx​ in terms of yyy.

(ii) Hence show that dydx=12(x−3)(19−x)\frac{dy}{dx} = \frac{1}{2\sqrt{(x-3)(19-x)}}dxdy​=2(x−3)(19−x)​1​.

[4]
c.

The normal to the curve at PPP intersects the xxx-axis at the point NNN.

Determine the exact area of triangle OPNOPNOPN, where OOO is the origin. Give your answer in the form aπ+bπ2a\pi + b\pi^2aπ+bπ2 where aaa and bbb are constants to be found.

[5]

3.6.6 Differentiation (A-level only) Questions

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