Let f(x)=6x3+13x2−4x−15f(x) = 6x^3 + 13x^2 - 4x - 15f(x)=6x3+13x2−4x−15.
Use the factor theorem to show that (2x+3)(2x + 3)(2x+3) is a factor of f(x)f(x)f(x).
Hence, using algebra, write f(x)f(x)f(x) as a product of three linear factors.
Solve, for π2<θ<π\frac{\pi}{2} < \theta < \pi2π<θ<π, the equation
6tan3θ+13tan2θ−4tanθ−15=0 6\tan^3 \theta + 13\tan^2 \theta - 4\tan \theta - 15 = 0 6tan3θ+13tan2θ−4tanθ−15=0giving your answers to 3 significant figures.
302 exam-style questions on WJEC A Level Maths 1.2 Algebra and Functions, covering 1.2.1 Algebra and Functions, 1.2.2 Algebra and Functions, 1.2.3 Algebra and Functions, 1.2.4 Algebra and Functions, 1.2.5 Algebra and Functions, 1.2.6 Algebra and Functions, 1.2.7 Algebra and Functions, 1.2.8 Algebra and Functions, 1.2.9 Algebra and Functions, 1.2.10 Algebra and Functions, 1.2.11 Algebra and Functions, and 1.2.12 Algebra and Functions. Each one has a worked solution and a mark scheme showing where the marks go.