Given that
g(x)=4x2−13x+13x−3 g(x) = \frac{4x^2 - 13x + 13}{x - 3} g(x)=x−34x2−13x+13Write g(x)g(x)g(x) in the form
Ax+B+Cx−3 Ax + B + \frac{C}{x - 3} Ax+B+x−3Cwhere AAA, BBB, and CCC are integers to be found.
Hence use algebraic integration to show that
∫46g(x) dx=α+βln3 \int_{4}^{6} g(x) \, dx = \alpha + \beta \ln 3 ∫46g(x)dx=α+βln3where α\alphaα and β\betaβ are integers to be found.
302 exam-style questions on WJEC A Level Maths 1.2 Algebra and Functions, covering 1.2.1 Algebra and Functions, 1.2.2 Algebra and Functions, 1.2.3 Algebra and Functions, 1.2.4 Algebra and Functions, 1.2.5 Algebra and Functions, 1.2.6 Algebra and Functions, 1.2.7 Algebra and Functions, 1.2.8 Algebra and Functions, 1.2.9 Algebra and Functions, 1.2.10 Algebra and Functions, 1.2.11 Algebra and Functions, and 1.2.12 Algebra and Functions. Each one has a worked solution and a mark scheme showing where the marks go.