Show that the equation 3sin2xtan2x=cos2x+23\sin 2x \tan 2x = \cos 2x + 23sin2xtan2x=cos2x+2 can be written in the form 4cos22x+2cos2x−3=04\cos^2 2x + 2\cos 2x - 3 = 04cos22x+2cos2x−3=0
Find all the values of x x\,x in the interval 0°⩽x<180° 0° \leqslant x < 180°\,0°⩽x<180° for which 3sin2xtan2x=cos2x+23\sin 2x \tan 2x = \cos 2x + 23sin2xtan2x=cos2x+2 Give your answers to 2 decimal places.
42 exam-style questions on OCR A Level Maths 1.5.15 Trigonometric equations. Each one has a worked solution and a mark scheme showing where the marks go.