Skip to content

Course home

Sign up

2 Statistics

EasyMediumHard
123456789101112131415161718192021222324252627282930313233343536373839404142434445464748495051525354555657585960616263646566676869707172737475767778798081828384858687888990919293949596979899100101102103104105106107108109110111112113114115116117118119120121122123124125126127128129130131132133134135136137138139140141142143144145146147148149150151152153154155156157158159160161162163164165166167168169170171172173174175176177178179180181182183184185186187188189190191192193194195196197198199200201202203204205206207208209210211212213214215216217218219220221222223224225226227228229230231232233234235236237238239240241242243244245246247248249250251252253254255256257258259260261262263264265266267268269270271272273274275276277278279280281282283284285286287288289290291292293294295296297298299300301302303304305306307308309310311312313314315316317318319320321322323324
Question 216

The variables x x\,x and y y\,y are recorded for 12 items, and the product moment correlation coefficient between x x\,x and y y\,y is -0.47.

The data are then coded using the changes of variable m=log⁡10xm = \log_{10} xm=log10​x and n=log⁡10yn = \log_{10} yn=log10​y. The product moment correlation coefficient between m m\,m and n n\,n is -0.83, and the regression line of n n\,n on m m\,m is

n=0.25−0.16mn = 0.25 - 0.16mn=0.25−0.16m

a.

Explain how these two correlation coefficients support the use of a model of the form y=axby = ax^{b}y=axb rather than a linear model in x x\,x and yyy.

[2]
b.

Show that the relationship between x x\,x and y y\,y can be written in the form y=axby = ax^{b}y=axb, and find the value of a a\,a to 3 significant figures and the value of bbb.

[5]
Markscheme

2 Statistics Questions

  1. A Level
  2. /Maths
  3. /2 Statistics

Question bank