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1.7.14 Stationary points

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Question 41

A curve has equation

y=2x3−3x2−12x+7 y = 2x^3 - 3x^2 - 12x + 7 y=2x3−3x2−12x+7
a.

Using calculus, find the xxx-coordinates of the stationary points of the curve.

[3]
b.

Justify, by further calculus, the nature of each stationary point.

[3]

1.7.14 Stationary points Questions

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