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3.2.9 Projectiles (A-level only)

3.2.9 Projectiles (A-level only)

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Question 17

In this question use g=9.8g = 9.8g=9.8 m s−2^{-2}−2.

A particle P P\,P is projected from a point O O\,O with speed U U\,U m s−1^{-1}−1 at an angle θ \theta\,θ above the horizontal. Air resistance is modelled as negligible. When P P\,P has moved a horizontal distance x x\,x metres, its height above O O\,O is y y\,y metres.

a.

By writing down expressions for x x\,x and for y y\,y in terms of the time ttt, and eliminating ttt, show that y=xtan⁡θ−gx22U2cos⁡2θy = x\tan\theta - \dfrac{gx^2}{2U^2\cos^2\theta}y=xtanθ−2U2cos2θgx2​.

[4]
b.

It is given that θ=45°\theta = 45°θ=45°, and that y=2y = 2y=2 when x=6x = 6x=6. Find the speed of P P\,P at the point where x=6x = 6x=6 and y=2y = 2y=2.

[5]
Markscheme

3.2.9 Projectiles (A-level only) Questions

  1. A Level
  2. /Maths
  3. /3.2.9 Projectiles (A-level only)

91 exam-style questions on OCR A Level Maths 3.2.9 Projectiles (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.

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