The flow rate of a lubricant, QQQ, in litres per hour, through a high-precision valve is modeled by the function Q(t)=3t3t2+1Q(t) = \frac{3t^3}{t^2+1}Q(t)=t2+13t3, where ttt is the time in hours since the valve was opened for 0≤t≤40 \le t \le 40≤t≤4.
An engineer is attempting to approximate the total volume of lubricant released, V=∫04Q(t) dtV = \int_{0}^{4} Q(t) \, dtV=∫04Q(t)dt, using the trapezium rule by splitting the interval into nnn equal strips.
When n=4n = 4n=4: (i) State the number of ordinates that the engineer uses. (ii) Calculate the approximation for the total volume VVV using this method. Give your answer correct to two decimal places.
Show that the exact volume of lubricant released is 24−32ln1724 - \frac{3}{2}\ln 1724−23ln17 litres. Fully justify your answer.
Explain what would happen to the engineer's approximation in part (a)(ii) as n→∞n \to \inftyn→∞.
125 exam-style questions on OCR A Level Maths 1.9 Numerical Methods (A-level only), covering 1.9.1 Locating roots by sign change (A-level only), 1.9.2 Failure of sign change methods (A-level only), 1.9.3 Simple iterative methods (A-level only), 1.9.4 Newton-Raphson method (A-level only), 1.9.5 Failure of iterative methods (A-level only), 1.9.6 Numerical integration (A-level only), and 1.9.7 Numerical methods in context (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.