A mechanical linkage is set at an obtuse angle ϕ\phiϕ. The equilibrium position of the linkage is determined by the equation
(4sinϕ+cosϕ)2+(2sinϕ−2cosϕ)2=10.4 (4 \sin \phi + \cos \phi)^2 + (2 \sin \phi - 2 \cos \phi)^2 = 10.4 (4sinϕ+cosϕ)2+(2sinϕ−2cosϕ)2=10.4Find the exact value of sinϕ\sin \phisinϕ. Fully justify your answer.
38 exam-style questions on OCR (MEI) A Level Maths 1.7.22 Proofs involving trigonometric functions (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.