A scientist is studying the potential of a chemical reaction, modeled by the equation
V=kt+12 V = k^t + 12 V=kt+12where kkk is a constant such that k>1k > 1k>1 and ttt is time. Sketch the graph of VVV against ttt.
On your sketch, show:
| ttt | 0 | 0.5 | 1 | 1.5 | 2 |
|---|---|---|---|---|---|
| R(t)R(t)R(t) | -3 | -2.2679 | -1 | 1.1962 | 5 |
The table shows corresponding values of time ttt and the rate of airflow R(t)R(t)R(t) in a ventilation shaft, where
R(t)=3t−4 R(t) = 3^t - 4 R(t)=3t−4Using the trapezium rule with all the values of R(t)R(t)R(t) in the given table, obtain an estimate for
∫02(3t−4) dt \int_{0}^{2} (3^t - 4) \, dt ∫02(3t−4)dtgiving your answer to 2 decimal places.
Using your answer to part (b) and making your method clear, estimate
(i)
∫02(3t+2) dt \int_{0}^{2} (3^t + 2) \, dt ∫02(3t+2)dt(ii)
∫02(3t+1−12) dt \int_{0}^{2} (3^{t+1} - 12) \, dt ∫02(3t+1−12)dt137 exam-style questions on OCR (MEI) A Level Maths 1.10 Numerical Methods (A-level only), covering 1.10.1 Locate roots by change of sign (A-level only), 1.10.2 When change of sign methods fail (A-level only), 1.10.3 Fixed point iteration (A-level only), 1.10.4 Newton-Raphson method (A-level only), 1.10.5 Convergence of iterations (A-level only), 1.10.6 Trapezium rule (A-level only), 1.10.7 Upper and lower bounds using rectangles (A-level only), and 1.10.8 Numerical methods to solve problems (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.