Skip to content

Course home

Sign up

3 Mechanics

EasyMediumHard
123456789101112131415161718192021222324252627282930313233343536373839404142434445464748495051525354555657585960616263646566676869707172737475767778798081828384858687888990919293949596979899100101102103104105106107108109110111112113114115116117118119120121122123124125126127128129130131132133134135136137138139140141142143144145146147148149150151152153154155156157158159160161162163164165166167168169170171172173174175176177178179180181182183184185186187188189190191192193194195196197198199200201202203204205206207208209210211212213214215216217218219220221222223224225226227228229230231232233
Question 167

Two research probes are dropped from rest at different altitudes during a planetary landing simulation. Probe P1 P_1\,P1​ is released from an altitude of A A\,A metres. Probe P2 P_2\,P2​ is released δ \delta\,δ seconds after P1 P_1\,P1​ from an altitude of rArArA, where r r\,r is a constant such that 0<r<10 < r < 10<r<1. Both probes reach the surface at the same time, exactly 6 seconds after the release of P1P_1P1​. Assuming the probes move under constant acceleration due to gravity g g\,g and air resistance is ignored,

prove that

δ=6(1−r) \delta = 6(1 - \sqrt{r}) δ=6(1−r​)

Fully justify your answer.

[6]
Markscheme

3 Mechanics Questions

  1. A Level
  2. /Maths
  3. /3 Mechanics

Question bank