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3 Mechanics

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Question 32

The velocity of a particle is v=(6t−2t2) m s−1v=(6t-2t^2)\text{ m s}^{-1}v=(6t−2t2) m s−1 for t≥0t\geq0t≥0. The particle is at the origin when t=0t=0t=0.

Find the distance of the particle from the origin when it first comes to instantaneous rest after t=0t=0t=0.

[4]
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3 Mechanics Questions

  1. A Level
  2. /Maths
  3. /3 Mechanics

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