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1.5.1 Laws of indices

What you'll learn

  • How to apply the laws of indices when multiplying, dividing and raising powers to powers.
  • What zero, negative and fractional indices mean.
  • How to work with any rational exponent and state necessary restrictions.
  • How to simplify expressions and solve equations involving indices.

Starting point: powers and indices

A power is an expression such as ana^nan. The number or expression aaa is the base, and nnn is the index or exponent.

For a positive integer nnn,

an=a⋅a⋅…⋅a⏟n factors.a^n=\underbrace{a\cdot a\cdot \ldots \cdot a}_{n\text{ factors}}.an=n factorsa⋅a⋅…⋅a​​.

For example, x4=x⋅x⋅x⋅xx^4=x\cdot x\cdot x\cdot xx4=x⋅x⋅x⋅x.

Definition

Rational exponent

A rational exponent is an exponent that can be written as a fraction mn\frac{m}{n}nm​, where mmm and nnn are integers and n≠0n\neq 0n=0. Integers are also rational because, for example, 3=313=\frac{3}{1}3=13​.

Multiplying powers with the same base

When powers with the same base are multiplied, add their indices:

am⋅an=am+n.a^m\cdot a^n=a^{m+n}.am⋅an=am+n.

This follows from counting the total number of factors of aaa. For example, a3⋅a2a^3\cdot a^2a3⋅a2 contains three factors of aaa followed by another two, giving five factors altogether.

Key Idea

Product law

Keep the base unchanged and add the indices:

am⋅an=am+n.a^m\cdot a^n=a^{m+n}.am⋅an=am+n.
Example

Multiplying powers

Simplify 3x5/2⋅4x7/33x^{5/2}\cdot 4x^{7/3}3x5/2⋅4x7/3.

  1. Multiply the numerical coefficients: 3⋅4=123\cdot 4=123⋅4=12.

  2. Add the indices of the common base xxx:

    52+73=156+146=296.\frac{5}{2}+\frac{7}{3} =\frac{15}{6}+\frac{14}{6} =\frac{29}{6}.25​+37​=615​+614​=629​.
  3. Therefore,

    3x5/2⋅4x7/3=12x29/6.3x^{5/2}\cdot 4x^{7/3}=12x^{29/6}.3x5/2⋅4x7/3=12x29/6.
Common Mistake

Multiplying the indices

Do not use am⋅an=amna^m\cdot a^n=a^{mn}am⋅an=amn. The indices are added, not multiplied. Multiplication of indices belongs to the power-of-a-power law.

Dividing powers with the same base

When powers with the same non-zero base are divided, subtract the index in the denominator from the index in the numerator:

aman=am−n,a≠0.\frac{a^m}{a^n}=a^{m-n},\qquad a\neq 0.anam​=am−n,a=0.

The restriction a≠0a\neq 0a=0 is needed because division by zero is undefined.

Key Idea

Quotient law

Keep the base unchanged and subtract the indices in the order top minus bottom:

aman=am−n.\frac{a^m}{a^n}=a^{m-n}.anam​=am−n.
Example

Dividing powers

Simplify

18p7/4q56p1/2q8,\frac{18p^{7/4}q^5}{6p^{1/2}q^8},6p1/2q818p7/4q5​,

where p≠0p\neq 0p=0 and q≠0q\neq 0q=0.

  1. Divide the coefficients: 18÷6=318\div 6=318÷6=3.

  2. Subtract the indices of ppp:

    74−12=74−24=54.\frac{7}{4}-\frac{1}{2} =\frac{7}{4}-\frac{2}{4} =\frac{5}{4}.47​−21​=47​−42​=45​.
  3. Subtract the indices of qqq: 5−8=−35-8=-35−8=−3.

  4. Hence,

    18p7/4q56p1/2q8=3p5/4q−3=3p5/4q3.\frac{18p^{7/4}q^5}{6p^{1/2}q^8} =3p^{5/4}q^{-3} =\frac{3p^{5/4}}{q^3}.6p1/2q818p7/4q5​=3p5/4q−3=q33p5/4​.

Raising a power to another power

When one power is raised to another power, multiply the indices:

(am)n=amn.\left(a^m\right)^n=a^{mn}.(am)n=amn.

Brackets matter: the outer index applies to the whole expression inside them.

Example

Raising a power to a power

Simplify (8x6)2/3\left(8x^6\right)^{2/3}(8x6)2/3, assuming x≥0x\geq 0x≥0.

  1. Apply the outer index to both factors:

    (8x6)2/3=82/3(x6)2/3.\left(8x^6\right)^{2/3}=8^{2/3}\left(x^6\right)^{2/3}.(8x6)2/3=82/3(x6)2/3.
  2. Evaluate the numerical power using the cube root:

    82/3=(83)2=22=4.8^{2/3}=\left(\sqrt[3]{8}\right)^2=2^2=4.82/3=(38​)2=22=4.
  3. Multiply the indices on xxx:

    (x6)2/3=x6⋅2/3=x4.\left(x^6\right)^{2/3}=x^{6\cdot 2/3}=x^4.(x6)2/3=x6⋅2/3=x4.
  4. Therefore,

    (8x6)2/3=4x4.\left(8x^6\right)^{2/3}=4x^4.(8x6)2/3=4x4.

Powers of products and quotients

An index can be distributed across multiplication:

(ab)n=anbn.(ab)^n=a^nb^n.(ab)n=anbn.

It can also be distributed across a quotient, provided the denominator is non-zero:

(ab)n=anbn,b≠0.\left(\frac{a}{b}\right)^n=\frac{a^n}{b^n},\qquad b\neq 0.(ba​)n=bnan​,b=0.
Common Mistake

Powers do not distribute over addition

In general, (a+b)n≠an+bn(a+b)^n\neq a^n+b^n(a+b)n=an+bn. For example, (2+3)2=25(2+3)^2=25(2+3)2=25, but 22+32=132^2+3^2=1322+32=13. The distribution laws apply to products and quotients, not sums or differences.

The zero index

For any non-zero base,

a0=1.a^0=1.a0=1.

This follows from the quotient law:

amam=am−m=a0.\frac{a^m}{a^m}=a^{m-m}=a^0.amam​=am−m=a0.

But the fraction on the left equals 1, so a0=1a^0=1a0=1.

Common Mistake

The base cannot be zero

The zero-index law requires a≠0a\neq 0a=0. At this level, 000^000 is treated as undefined.

Negative indices

A negative index means take the reciprocal of the corresponding positive power. The reciprocal of a non-zero number kkk is 1k\frac{1}{k}k1​.

a−n=1an,a≠0.a^{-n}=\frac{1}{a^n},\qquad a\neq 0.a−n=an1​,a=0.

More generally,

(ab)−n=(ba)n,\left(\frac{a}{b}\right)^{-n} =\left(\frac{b}{a}\right)^n,(ba​)−n=(ab​)n,

provided all denominators are non-zero.

Key Idea

Meaning of a negative index

A negative index does not make the value negative. It tells you to invert the base:

a−n=1an.a^{-n}=\frac{1}{a^n}.a−n=an1​.
Example

Removing negative indices

Write 6x−2y−3\frac{6x^{-2}}{y^{-3}}y−36x−2​ using positive indices only, where x≠0x\neq 0x=0 and y≠0y\neq 0y=0.

  1. Rewrite x−2x^{-2}x−2 as its reciprocal:

    x−2=1x2.x^{-2}=\frac{1}{x^2}.x−2=x21​.
  2. Dividing by y−3y^{-3}y−3 is equivalent to multiplying by its reciprocal, y3y^3y3.

  3. Therefore,

    6x−2y−3=6⋅1x2⋅y3=6y3x2.\frac{6x^{-2}}{y^{-3}} =6\cdot\frac{1}{x^2}\cdot y^3 =\frac{6y^3}{x^2}.y−36x−2​=6⋅x21​⋅y3=x26y3​.
Tip

Moving factors across a fraction bar

A factor with a negative index becomes a positive-index factor when moved across the fraction bar. For example, x−3y−2=y2x3\frac{x^{-3}}{y^{-2}}=\frac{y^2}{x^3}y−2x−3​=x3y2​.

Fractional indices

A fractional index represents a root. For a positive integer nnn,

a1/n=an.a^{1/n}=\sqrt[n]{a}.a1/n=na​.

The denominator of the index tells you which root to take:

a1/2=a,a1/3=a3.a^{1/2}=\sqrt{a}, \qquad a^{1/3}=\sqrt[3]{a}.a1/2=a​,a1/3=3a​.

For a general rational exponent,

am/n=(an)m=amn.a^{m/n}=\left(\sqrt[n]{a}\right)^m=\sqrt[n]{a^m}.am/n=(na​)m=nam​.

The numerator gives the power and the denominator gives the root.

Example

Evaluating a fractional power

Evaluate 813/481^{3/4}813/4.

  1. Interpret the denominator 4 as a fourth root:

    813/4=(814)3.81^{3/4}=\left(\sqrt[4]{81}\right)^3.813/4=(481​)3.
  2. Since 81=3481=3^481=34, its positive fourth root is 3.

  3. Raise this result to the power 3:

    813/4=33=27.81^{3/4}=3^3=27.813/4=33=27.
Example

Combining negative and fractional indices

Evaluate 32−2/532^{-2/5}32−2/5.

  1. Use the negative index to form a reciprocal:

    32−2/5=1322/5.32^{-2/5}=\frac{1}{32^{2/5}}.32−2/5=322/51​.
  2. Use the denominator 5 to take the fifth root: 325=2\sqrt[5]{32}=2532​=2.

  3. Use the numerator 2 as the power:

    322/5=22=4.32^{2/5}=2^2=4.322/5=22=4.
  4. Therefore,

    32−2/5=14.32^{-2/5}=\frac{1}{4}.32−2/5=41​.

Restrictions for rational exponents

When working only with real numbers, even roots of negative numbers are not defined. Therefore, an expression such as a1/2a^{1/2}a1/2 requires a≥0a\geq 0a≥0.

Odd roots of negative numbers are real. For example,

(−8)1/3=−2.(-8)^{1/3}=-2.(−8)1/3=−2.

If a rational exponent is negative, the base must also be non-zero because the result involves a reciprocal.

Common Mistake

Check the base and denominator

For arbitrary rational indices, the index laws are most straightforward when bases are positive. With negative bases, first write the exponent in its simplest fractional form and check that any required root is real. For example, (−16)1/2(-16)^{1/2}(−16)1/2 is not real, while (−8)2/3=4(-8)^{2/3}=4(−8)2/3=4.

Simplifying a full expression

Many questions require several laws in the same calculation. Work with coefficients and each base separately.

Example

Using several index laws

Simplify

(2x3/2y−1)24x−1y3,\frac{\left(2x^{3/2}y^{-1}\right)^2}{4x^{-1}y^3},4x−1y3(2x3/2y−1)2​,

using positive indices, where x>0x>0x>0 and y≠0y\neq 0y=0.

  1. Apply the power to each factor in the numerator:

    (2x3/2y−1)2=4x3y−2.\left(2x^{3/2}y^{-1}\right)^2 =4x^3y^{-2}.(2x3/2y−1)2=4x3y−2.
  2. Divide the coefficients and subtract the indices of each common base:

    4x3y−24x−1y3=x3−(−1)y−2−3=x4y−5.\frac{4x^3y^{-2}}{4x^{-1}y^3} =x^{3-(-1)}y^{-2-3} =x^4y^{-5}.4x−1y34x3y−2​=x3−(−1)y−2−3=x4y−5.
  3. Replace the negative index with a reciprocal:

    x4y−5=x4y5.x^4y^{-5}=\frac{x^4}{y^5}.x4y−5=y5x4​.

Solving equations involving indices

Fractional indices can often be removed by raising both sides of an equation to a suitable power. You must then check that your solution satisfies the original equation and any domain restrictions.

Example

Solving a fractional-index equation

Solve x3/2=64x^{3/2}=64x3/2=64 for real xxx.

  1. Because x3/2x^{3/2}x3/2 involves a square root, the real domain requires x≥0x\geq 0x≥0.

  2. Raise both sides to the reciprocal power 23\frac{2}{3}32​:

    x=(64)2/3.x=\left(64\right)^{2/3}.x=(64)2/3.
  3. Evaluate by taking the cube root and then squaring:

    x=(643)2=42=16.x=\left(\sqrt[3]{64}\right)^2=4^2=16.x=(364​)2=42=16.
  4. Check in the original equation:

    163/2=(16)3=43=64.16^{3/2}=\left(\sqrt{16}\right)^3=4^3=64.163/2=(16​)3=43=64.

    Therefore, x=16x=16x=16.

Exam technique

In the exam

  1. Identify whether you should add, subtract or multiply indices: multiplication of like bases means add, division means subtract, and a power of a power means multiply.
  2. Simplify fractional indices carefully: the denominator gives the root and the numerator gives the power.
  3. State restrictions when relevant, especially for denominators, negative indices and even roots, and leave exact answers unless a decimal is requested.
  4. In longer expressions, deal separately with the numerical coefficient and each algebraic base, then rewrite negative indices as positive indices if required.
Self review

Check yourself

  • Can you simplify x5/3⋅x−1/2x^{5/3}\cdot x^{-1/2}x5/3⋅x−1/2 as a single power of xxx?
  • Can you evaluate 27−2/327^{-2/3}27−2/3 exactly?
  • What restrictions are needed for the real expression 1x1/2\frac{1}{x^{1/2}}x1/21​?

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