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3.2 Kinematics

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Question 2
59%

The acceleration of a particle after t t\,t seconds is given by (4t−8) ms−2(4t - 8) \text{ ms}^{-2}(4t−8) ms−2. Given the velocity (vvv) of the particle is 6 ms-1 when t=0t = 0t=0.

a.

Find v v\,v in terms of ttt.

[3]
b.

Find the distance between the two points the particle is instantaneously at rest.

[7]

3.2 Kinematics Questions

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