A scientist monitoring the growth of a synthetic crystal determines that the rate of change of its mass, MMM in milligrams, with respect to time ttt in hours, is given by:
dMdt=5t4−3t34,t>0 \frac{dM}{dt} = 5t^4 - \frac{3}{\sqrt[4]{t^3}}, \quad t > 0 dtdM=5t4−4t33,t>0Determine the general expression for the mass M(t)M(t)M(t).
80 exam-style questions on OCR (MEI) A Level Maths 1.9.20 Integrate kx^n. Each one has a worked solution and a mark scheme showing where the marks go.