Given that y=tanxy = \tan xy=tanx, use the quotient rule to show that
dydx=sec2x \frac{dy}{dx} = \sec^2 x dxdy=sec2xThe cross-section of a high-precision optical lens is modeled by the region bounded by the curve y=3tan2x+2y = 3\tan^2 x + 2y=3tan2x+2, the xxx-axis, and the vertical boundaries x=π6x = \frac{\pi}{6}x=6π and x=π3x = \frac{\pi}{3}x=3π.
Show that the area of this cross-section is
33−3−π6 3\sqrt{3} - \sqrt{3} - \frac{\pi}{6} 33−3−6πwhich simplifies to
23−π6 2\sqrt{3} - \frac{\pi}{6} 23−6πFully justify your answer.
31 exam-style questions on OCR (MEI) A Level Maths 1.9.24 Integrate e^kx, 1/x, sin kx, cos kx (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.