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Card 1 of 20

Rewrite tan⁡θ\tan\thetatanθ using sine and cosine.

A

For a right-angled triangle, sin⁡θ=\sin\theta=sinθ= oppositehypotenuse\boxed{\dfrac{\text{opposite}}{\text{hypotenuse}}}hypotenuseopposite​​.

B

In radians, tan⁡θ\tan\thetatanθ is undefined when θ=π2+nπ, n∈Z\boxed{\theta=\dfrac{\pi}{2}+n\pi,\ n\in\mathbb Z}θ=2π​+nπ, n∈Z​.

C

θ=0∘, 60∘, 180∘, 300∘\theta=0^\circ,\ 60^\circ,\ 180^\circ,\ 300^\circθ=0∘, 60∘, 180∘, 300∘

D

tan⁡θ≡sin⁡θcos⁡θ\tan\theta\equiv\dfrac{\sin\theta}{\cos\theta}tanθ≡cosθsinθ​, where cos⁡θ≠0\cos\theta\neq0cosθ=0.

Card 1 of 20

1.7.7 Identity tan = sin/cos Flashcards

  1. A Level
  2. /Maths
  3. /1.7.7 Identity tan = sin/cos

20 flashcards on OCR (MEI) A Level Maths 1.7.7 Identity tan = sin/cos: the key formulae, methods and definitions you need to recall for Component 01, Component 02 and Component 03.

Flashcards