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1.4 Graphs

1.4 Graphs

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Question 14

The elevation of a landscape is modeled by a cubic function y=f(x)y = f(x)y=f(x), where y y\,y is the height in meters and x x\,x is the horizontal distance from a fixed point. A sketch of the curve y=f(x)y = f(x)y=f(x) shows that it starts from the bottom-left, rises to a local maximum, passes through the yyy-axis at (0,4)(0, 4)(0,4), and then descends to touch the xxx-axis at a local minimum point (3,0)(3, 0)(3,0) before rising again. The curve also intersects the xxx-axis at the point (−5,0)(-5, 0)(−5,0).

On separate diagrams, sketch the curve with equation:

a.

y=f(x−5)y = f(x - 5)y=f(x−5)

On each diagram, show clearly the coordinates of all the points where the curve cuts or touches the coordinate axes.

[3]
b.

y=f(−12x)\displaystyle y = f\left(-\frac{1}{2}x\right)y=f(−21​x)

On each diagram, show clearly the coordinates of all the points where the curve cuts or touches the coordinate axes.

[4]
Markscheme

1.4 Graphs Questions

  1. A Level
  2. /Maths
  3. /1.4 Graphs

33 exam-style questions on OCR (MEI) A Level Maths 1.4 Graphs, covering 1.4.1 Graphs of functions, 1.4.2 Intersection points with axes, 1.4.3 Completing the square for a quadratic curve, 1.4.4 Sketch graphs of simple functions, 1.4.5 Stationary points when curve sketching, 1.4.6 Graphs of reciprocal-type functions, 1.4.7 Single transformations of graphs, 1.4.8 Combined transformations of graphs (A-level only), and 1.4.9 Stationary points of inflection (A-level only). Each one has a worked solution and a mark scheme showing where the marks go.

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