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1.5.16 Gradient of a parametric curve (A-level only)

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Question 17

A precision laser cutting tool follows a path defined by the relationship between its lateral displacement, xxx mm, and the angle of its guide-rail, yyy radians, given by

x=16sin⁡2y+5,0⩽y⩽π2 x = 16\sin^2 y + 5, \quad 0 \leqslant y \leqslant \frac{\pi}{2} x=16sin2y+5,0⩽y⩽2π​

The point P(k,π3)P\left(k, \frac{\pi}{3}\right)P(k,3π​) lies on this path.

a.

Verify that k=17k = 17k=17.

[2]
bi.

Find dxdy\frac{dx}{dy}dydx​ in terms of yyy.

[2]
bii.

Hence show that dydx=12x−521−x\frac{dy}{dx} = \frac{1}{2\sqrt{x-5}\sqrt{21-x}}dxdy​=2x−5​21−x​1​.

[3]
c.

The normal to the path at PPP cuts the xxx-axis at the point NNN.

Find the exact area of triangle OPNOPNOPN, where OOO is the origin. Give your answer in the form aπ+bπ2a\pi + b\pi^2aπ+bπ2 where aaa and bbb are constants.

[5]

1.5.16 Gradient of a parametric curve (A-level only) Questions

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