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1.5 Coordinate Geometry

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Question 23

A curve has the parametric equations

x=sec⁡2t,y=2tan⁡t,0<t<π2 x = \sec^2 t, \quad y = 2\tan t, \quad 0 < t < \frac{\pi}{2} x=sec2t,y=2tant,0<t<2π​
a.

Find an expression for dydx\displaystyle \frac{dy}{dx}dxdy​ in terms of ttt.

[3]
b.

Find an equation of the tangent to the curve when t=π3\displaystyle t = \frac{\pi}{3}t=3π​.

[5]
c.

Find a cartesian equation for the curve.

[4]

1.5 Coordinate Geometry Questions

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