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3 Mechanics

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Question 96

A small stone is released from rest and falls vertically through 19.6 m. Model the stone as a particle moving freely under gravity. Use g=9.8 m s−2g=9.8\text{ m s}^{-2}g=9.8 m s−2.

a.

Find the time taken for the stone to fall 19.6 m.

[2]
b.

Find the speed of the stone at this instant.

[2]
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3 Mechanics Questions

  1. A Level
  2. /Maths
  3. /3 Mechanics

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