The acceleration of a particle at time t t\,t seconds is a=(4t−8) m s−2a=(4t-8)\text{ m s}^{-2}a=(4t−8) m s−2. At t=0t=0t=0 its velocity is 6 m s-1.
Find v v\,v in terms of ttt.
Find the distance between the two points at which the particle is instantaneously at rest.