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1.8.8 Integration by substitution (A-level only)

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Question 56

The concentration C C\,C of a chemical catalyst in a specialized solvent depends on the depth ddd (in cm) according to the model

C=502(3d−k),d≠k3 C = \frac{50}{2(3d - k)}, \quad d \neq \frac{k}{3} C=2(3d−k)50​,d=3k​

where k k\,k is a positive constant and k≠12k \neq 12k=12.

a.

Find dCdd\displaystyle \frac{dC}{dd}dddC​ giving your answer in simplest form in terms of kkk.

[3]
b.

The point P P\,P with ddd-coordinate 4 lies on the curve. Given that the rate of change of concentration with respect to depth at P P\,P is -3,

find the two possible values of kkk.

[3]
c.

Given also that k<12k < 12k<12,

find the equation of the normal to the curve at PPP, writing your answer in the form ad+bC+c=0ad + bC + c = 0ad+bC+c=0, where aaa, bbb, and c c\,c are integers to be found.

[4]
d.

Show, using algebraic integration, that

∫35502(3d−k) dd=λln⁡2 \int_{3}^{5} \frac{50}{2(3d - k)} \, dd = \lambda \ln 2 ∫35​2(3d−k)50​dd=λln2

where λ \lambda\,λ is a constant to be found.

[4]

1.8.8 Integration by substitution (A-level only) Questions

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