One of the terms in the binomial expansion of (2+bx)5(2 + bx)^5(2+bx)5, where b b\,b is a constant, is 720x2720x^2720x2.
Find the possible values of bbb.
Hence find the term independent of x x\,x in the expansion of (14+1x5)(2+bx)5\left( \frac{1}{4} + \frac{1}{x^5} \right) (2 + bx)^5(41+x51)(2+bx)5
