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10.4 Solving Trigonometric Equations

10.4 Solving Trigonometric Equations

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Question 6
a.

Show that the equation

2sin⁡2x=7cos⁡x+5 2\sin^2 x = 7\cos x + 5 2sin2x=7cosx+5

can be written in the form

2cos⁡2x+7cos⁡x+3=0 2\cos^2 x + 7\cos x + 3 = 0 2cos2x+7cosx+3=0
[3]
b.

Hence solve, for 0≤x<360∘0 \leq x < 360^\circ0≤x<360∘, the equation

2sin⁡2x=7cos⁡x+5 2\sin^2 x = 7\cos x + 5 2sin2x=7cosx+5
[5]
Markscheme

10.4 Solving Trigonometric Equations Questions

  1. A Level
  2. /Maths
  3. /10.4 Solving Trigonometric Equations

11 exam-style questions on Edexcel A Level Maths 10.4 Solving Trigonometric Equations. Each one has a worked solution and a mark scheme showing where the marks go.

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