7.3 Solving Trigonometric Equations

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Show that the equation

$2sin⁡θcos⁡θ3sin⁡θ−2=3tan⁡θ,sin⁡θ≠23\frac{2\sin\theta \cos\theta}{3\sin\theta - 2} = 3\tan\theta, \quad \sin\theta \neq \frac{2}{3}$

can be written in the form

$2sin⁡3θ+9sin⁡2θ−8sin⁡θ=02\sin^3\theta + 9\sin^2\theta - 8\sin\theta = 0$

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Hence solve, for $−π2<x<π2-\frac{\pi}{2} < x < \frac{\pi}{2}$

$2sin⁡xcos⁡x3sin⁡x−2=3tan⁡x\frac{2\sin x \cos x}{3\sin x - 2} = 3\tan x$

giving your answers to 3 decimal places where appropriate.

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7.3 Solving Trigonometric Equations Questions

Practise Edexcel A Level Maths 7.3 Solving Trigonometric Equations with exam-style questions for A Level Maths. 29 questions, matched to the Edexcel A Level Maths (9MA0) specification and written in Paper 1, Paper 2 and Paper 3 style. Every question includes a full worked solution and mark scheme, so you can see where marks are awarded rather than just whether you got the answer right.