Use the identity sin2θ+cos2θ=1\sin^2\theta + \cos^2\theta = 1sin2θ+cos2θ=1 to prove that 1+tan2θ=sec2θ1 + \tan^2\theta = \sec^2\theta1+tan2θ=sec2θ.
Solve, for 0≤θ≤2π0 \leq \theta \leq 2\pi0≤θ≤2π, the equation,
sec2θ+tan2θ=3 \sec^2\theta + \tan^2\theta = 3 sec2θ+tan2θ=3Give your answers in terms of π\piπ.
16 exam-style questions on Edexcel A Level Maths 6.3 Using Sec x, Cosec x and Cot x. Each one has a worked solution and a mark scheme showing where the marks go.