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5.5 Small Angle Approximations

5.5 Small Angle Approximations

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Question 18

In a precision laser alignment system, the deviation ratio DDD for a small angle of incidence θ\thetaθ (measured in radians, where θ≠0\theta \neq 0θ=0) is modeled by the function:

D(θ)=3θsin⁡(4θ)1−cos⁡(5θ) D(\theta) = \frac{3\theta \sin(4\theta)}{1 - \cos(5\theta)} D(θ)=1−cos(5θ)3θsin(4θ)​

Using small angle approximations, show that for small values of θ\thetaθ, D(θ)≈KD(\theta) \approx KD(θ)≈K where KKK is a constant to be determined.

[3]
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5.5 Small Angle Approximations Questions

  1. A Level
  2. /Maths
  3. /5.5 Small Angle Approximations

25 exam-style questions on Edexcel A Level Maths 5.5 Small Angle Approximations. Each one has a worked solution and a mark scheme showing where the marks go.

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