Show that 1(2+3x)2=14(1+32x)−2\displaystyle \frac{1}{(2+3x)^2}=\frac{1}{4}(1+\frac{3}{2}x)^{-2}(2+3x)21=41(1+23x)−2
Hence work out the first three terms in the binomial expansion of 1(2+3x)2\displaystyle \frac{1}{(2+3x)^2}(2+3x)21
Write down the range of values of x x\,x for which the expansion is valid.
408 exam-style questions on Edexcel A Level Maths Binomial Expansion, covering 4.1 Expanding (1 + x)^n, 4.2 Expanding (a + bx)^n, and 4.3 Using Partial Fractions. Each one has a worked solution and a mark scheme showing where the marks go.