One of the terms in the binomial expansion of (2+bx)5(2 + bx)^5(2+bx)5, where b b\,b is a constant, is 720x2720x^2720x2.
Find the possible values of bbb.
Hence find the term independent of x x\,x in the expansion of
(14+1x5)(2+bx)5 \left( \frac{1}{4} + \frac{1}{x^5} \right) (2 + bx)^5 (41+x51)(2+bx)599 exam-style questions on Edexcel A Level Maths 4.2 Expanding (a + bx)^n. Each one has a worked solution and a mark scheme showing where the marks go.