Relative to a fixed origin OOO, the point A A\,A has position vector (2i−j+k)(2\mathbf{i} - \mathbf{j} + \mathbf{k})(2i−j+k), the point B B\,B has position vector (3i−3j)(3\mathbf{i} - 3\mathbf{j})(3i−3j), and the point C C\,C has position vector (i−2j−k)(\mathbf{i} - 2\mathbf{j} - \mathbf{k})(i−2j−k).
Find BC⃗\vec{BC}BC
Find CB⃗\vec{CB}CB
Show that the quadrilateral OABC OABC\,OABC is a parallelogram, giving reasons for your answer.
309 exam-style questions on Edexcel A Level Maths Vectors, covering 12.1 3D Coordinates, 12.2 Vectors in 3D, 12.3 Solving Geometric Problems, and 12.4 Application to Mechanics. Each one has a worked solution and a mark scheme showing where the marks go.