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11.5 Integration by Substitution

11.5 Integration by Substitution

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Question 4

The profile of a specialized aerodynamic sail is modeled by a curve with parametric equations

x=36−6t,y=t336+6t,0≤t≤6 x = \sqrt{36-6t}, \quad y = \frac{t^3}{\sqrt{36+6t}}, \quad 0 \le t \le 6 x=36−6t​,y=36+6t​t3​,0≤t≤6

The curve intersects the yyy-axis at the point where t=6t=6t=6 and the xxx-axis at the point where t=0t=0t=0. The region RRR is bounded by the curve and the positive xxx and yyy axes.

a.

Show that the area of RRR is given by

K∫06t31296−36t2 dt K \int_{0}^{6} \frac{t^3}{\sqrt{1296-36t^2}} \, dt K∫06​1296−36t2​t3​dt

where KKK is a constant to be found.

[4]
b.

Using the substitution u=1296−36t2u = 1296 - 36t^2u=1296−36t2, or otherwise, find the exact area of RRR.

[7]
Markscheme

11.5 Integration by Substitution Questions

  1. A Level
  2. /Maths
  3. /11.5 Integration by Substitution

59 exam-style questions on Edexcel A Level Maths 11.5 Integration by Substitution. Each one has a worked solution and a mark scheme showing where the marks go.

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