The monthly rate of increase of a fish population in a reservoir is equal to 1.5% of the current population. P P\,P is the population in hundreds and t t\,t is the time in months.
Write down a differential equation for this relationship.
Show that P=Ae0.015tP = Ae^{0.015t}P=Ae0.015t where A A\,A is a constant.
Given that the initial population is 800 fish. Find the population after 2 years (24 months), to the nearest whole number.
50 exam-style questions on Edexcel A Level Maths 11.11 Modelling with Differential Equations. Each one has a worked solution and a mark scheme showing where the marks go.