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6.3 Projection at Any Angle

6.3 Projection at Any Angle

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Question 50

In this question use g=9.8 m s−2g = 9.8 \text{ m s}^{-2}g=9.8 m s−2.

A decorative water fountain nozzle is designed to eject water droplets vertically upwards with an initial speed of 11.2 m s-1. The manufacturer’s catalog states that the water can reach a maximum vertical height of 6.4 metres above the nozzle.

a.

(i) Verify the manufacturer's claim by calculating the maximum height of a droplet when fired vertically.

(ii) Identify two modelling assumptions used in this verification.

[4]
b.

The nozzle's alignment can deviate by as much as 20∘20^{\circ}20∘ from the vertical.

The range of possible maximum vertical heights, h h\,h metres, reached by the droplets can be expressed as:

k≤h≤6.4 k \le h \le 6.4 k≤h≤6.4

Calculate the value of kkk, giving your answer to two significant figures.

[3]
Markscheme

6.3 Projection at Any Angle Questions

  1. A Level
  2. /Maths
  3. /6.3 Projection at Any Angle

57 exam-style questions on Edexcel A Level Maths 6.3 Projection at Any Angle. Each one has a worked solution and a mark scheme showing where the marks go.

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