Skip to content

Course home

Sign up

6.4 Projectile Motion Formulae

MediumHard
123456
Question 4

A stone is thrown from the origin O O\,O with initial velocity W ms−1W \text{ ms}^{-1}W ms−1 at an angle β \beta\,β to the horizontal. At time t t\,t seconds, its horizontal and vertical displacements are x x\,x and y y\,y respectively.

a.

Prove that

y=xtan⁡β−gx22W2cos⁡2β y = x \tan \beta - \frac{g x^2}{2 W^2 \cos^2 \beta} y=xtanβ−2W2cos2βgx2​
[4]
b.

Given that tan⁡β=34\displaystyle \tan \beta = \frac{3}{4}tanβ=43​ and that when x=4x = 4x=4, y=1y = 1y=1, find the speed of the stone at the point where x=4x = 4x=4.

[6]
Markscheme

6.4 Projectile Motion Formulae Questions

  1. A Level
  2. /Maths
  3. /6.4 Projectile Motion Formulae

10 exam-style questions on Edexcel A Level Maths 6.4 Projectile Motion Formulae. Each one has a worked solution and a mark scheme showing where the marks go.

Question bank