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6.4 Projectile Motion Formulae

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Question 1

A ball S S\,S is thrown from a point O O\,O with initial speed V ms−1V \text{ ms}^{-1}V ms−1 at an angle of elevation θ\thetaθ. After traveling a horizontal distance xxx, its height above the level of O O\,O is yyy.

a.

Show that

y=xtan⁡θ−gx22V2cos⁡2θ y = x \tan \theta - \frac{g x^2}{2 V^2 \cos^2 \theta} y=xtanθ−2V2cos2θgx2​
[4]
b.

Given that θ=45∘\theta = 45^\circθ=45∘ and that when x=10x = 10x=10, y=2y = 2y=2, find the speed of S S\,S at the point where x=10x = 10x=10 and y=2y = 2y=2.

[6]
Markscheme

6.4 Projectile Motion Formulae Questions

  1. A Level
  2. /Maths
  3. /6.4 Projectile Motion Formulae

10 exam-style questions on Edexcel A Level Maths 6.4 Projectile Motion Formulae. Each one has a worked solution and a mark scheme showing where the marks go.

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