A particle P P\,P is projected from a point O O\,O with velocity Vms−1V\text{ms}^{-1}Vms−1 at an angle of ϕ∘ \phi^\circ\,ϕ∘ to the horizontal. When P P\,P has moved a horizontal distance xxx, its height above O O\,O is yyy.
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y=xtanϕ−gx22V2cos2ϕ y = x \tan \phi - \frac{g x^2}{2 V^2 \cos^2 \phi} y=xtanϕ−2V2cos2ϕgx2230 exam-style questions on Edexcel A Level Maths Projectiles, covering 6.1 Horizontal Projection, 6.2 Horizontal and Vertical Components, 6.3 Projection at Any Angle, and 6.4 Projectile Motion Formulae. Each one has a worked solution and a mark scheme showing where the marks go.